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So now, for every one of those output nodes, we do the same thing we were doing in the pull step. But we add a couple of additional checks to our logic:。新收录的资料对此有专业解读
pixel[1] = pixel[1] 0.04045f ? powf((pixel[1] + 0.055f) / 1.055f, 2.4f) : pixel[1] / 12.92f;。新收录的资料对此有专业解读
This is certainly a simplification.。新收录的资料是该领域的重要参考